Table.find
From GiderosMobile
Available since: Gideros 2022.3
Class: table
Description
Within the given array-like table t, find the first occurrence of value, starting from index or the beginning if not provided. If the value is not found, nil is returned. <syntaxhighlight lang="lua"> (any) = table.find(t,value,index) </source>
A linear search algorithm is performed
Parameters
t: (table) source table
value: (any) value to find
index: (number) index to start the search at optional
Return values
Returns (any) the index of first occurence of value or nil if not found
Example
<syntaxhighlight lang="lua"> local t = {"a", "b", "c", "d", "e"} print(table.find(t, "d")) --> 4 print(table.find(t, "z")) --> nil, because z is not in the table print(table.find(t, "b", 3)) --> nil, because b appears before index 3 </source>
