Utf8.offset
From GiderosMobile
Available since: Gideros 2016.06
Description
Returns the position (in bytes) where the encoding of the n-th character of s (counting from position i) starts. A negative n gets characters before position i. The default for i is 1 when n is non-negative and #s + 1 otherwise, so that utf8.offset(s, -n) gets the offset of the n-th character from the end of the string. If the specified character is neither in the subject nor right after its end, the function returns nil. As a special case, when n is 0 the function returns the start of the encoding of the character that contains the i-th byte of s. This function assumes that s is a valid UTF-8 string.
(number), = utf8.offset(sni,)
's: (string) '
'n: (number) '
i: (number) optional
Returns (number) position (in bytes)
